(x^2+4)(x-3)=0

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Solution for (x^2+4)(x-3)=0 equation: 


Simplifying
(x2 + 4)(x + -3) = 0

Reorder the terms:
(4 + x2)(x + -3) = 0

Reorder the terms:
(4 + x2)(-3 + x) = 0

Multiply (4 + x2) * (-3 + x)
(4(-3 + x) + x2(-3 + x)) = 0
((-3 * 4 + x * 4) + x2(-3 + x)) = 0
((-12 + 4x) + x2(-3 + x)) = 0
(-12 + 4x + (-3 * x2 + x * x2)) = 0
(-12 + 4x + (-3x2 + x3)) = 0
(-12 + 4x + -3x2 + x3) = 0

Solving
-12 + 4x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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